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转 Google地图百度地图GPS经纬度偏移转换(JAVA) 转
阅读量:6150 次
发布时间:2019-06-21

本文共 4760 字,大约阅读时间需要 15 分钟。

  hot3.png

转http://my.oschina.net/Thinkeryjgfn/blog/402565

 

js版本。

https://github.com/wandergis/coordtransform

 

不多说,直接代码,Java版

主要就是Google地图,百度地图,GPS经纬度偏移转换

GCJ-02转换BD-09,Google地图经纬度转百度地图经纬度

BD-09转换GCJ-02,百度转google
WGS-84 到 GCJ-02 的转换(即 GPS 加偏)

/** * 用于构造地图中的坐标点 * @author lw * **/public class Point {		private double lat;// 纬度	private double lng;// 经度		public Point() {	}		public Point(double lng, double lat) {		this.lng = lng;		this.lat = lat;	}	@Override	public boolean equals(Object obj) {		if (obj instanceof Point) {			Point bmapPoint = (Point) obj;			return (bmapPoint.getLng() == lng && bmapPoint.getLat() == lat) ? true : false;		} else {			return false;		}	}		public double getLat() {		return lat;	}	public void setLat(double lat) {		this.lat = lat;	}	public double getLng() {		return lng;	}	public void setLng(double lng) {		this.lng = lng;	}		@Override	public String toString() {		return "Point [lat=" + lat + ", lng=" + lng + "]";	}	}

 

/** * 地图坐标转换 google,baidu,gps * @author lw * @Time 2015年4月16日18:19:16 *  * */public class CoordinateConversion {	private static final double x_pi = 3.14159265358979324 * 3000.0 / 180.0;		private static final double pi = 3.14159265358979324;	private static final double a = 6378245.0;	private static final double ee = 0.00669342162296594323;		/**	 * gg_lat 纬度	 * gg_lon 经度	 * GCJ-02转换BD-09	 * Google地图经纬度转百度地图经纬度	 * */	public static Point google_bd_encrypt(double gg_lat, double gg_lon){		Point point=new Point();		double x = gg_lon, y = gg_lat;		double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);		double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi); 		double bd_lon = z * Math.cos(theta) + 0.0065;		double bd_lat = z * Math.sin(theta) + 0.006;		point.setLat(bd_lat);		point.setLng(bd_lon);		return point;	}		/**	 * wgLat 纬度	 * wgLon 经度	 * BD-09转换GCJ-02	 * 百度转google	 * */	public static Point bd_google_encrypt(double bd_lat, double bd_lon){		Point point=new Point();	    double x = bd_lon - 0.0065, y = bd_lat - 0.006;  	    double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);  	    double theta =Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);  	    double gg_lon = z * Math.cos(theta);  	    double gg_lat = z * Math.sin(theta);  	    point.setLat(gg_lat);	    point.setLng(gg_lon);	    return point;	}				/**	 * wgLat 纬度	 * wgLon 经度	 * WGS-84 到 GCJ-02 的转换(即 GPS 加偏)	 * */	public static Point wgs_gcj_encrypts(double wgLat, double wgLon) {		Point point=new Point();		if (outOfChina(wgLat, wgLon)) {			point.setLat(wgLat);			point.setLng(wgLon);			return point;		}		double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);		double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);		double radLat = wgLat / 180.0 * pi;		double magic = Math.sin(radLat);		magic = 1 - ee * magic * magic;		double sqrtMagic = Math.sqrt(magic);		dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);		dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);		double lat = wgLat + dLat;		double lon = wgLon + dLon;		point.setLat(lat);		point.setLng(lon);		return point;	}			public static void transform(double wgLat, double wgLon, double[] latlng) {		if (outOfChina(wgLat, wgLon)) {			latlng[0] = wgLat;			latlng[1] = wgLon;			return;		}		double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);		double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);		double radLat = wgLat / 180.0 * pi;		double magic = Math.sin(radLat);		magic = 1 - ee * magic * magic;		double sqrtMagic = Math.sqrt(magic);		dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);		dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);		latlng[0] = wgLat + dLat;		latlng[1] = wgLon + dLon;	}	private static boolean outOfChina(double lat, double lon) {		if (lon < 72.004 || lon > 137.8347)			return true;		if (lat < 0.8293 || lat > 55.8271)			return true;		return false;	}	private static double transformLat(double x, double y) {		double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));		ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;		ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;		ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;		return ret;	}	private static double transformLon(double x, double y) {		double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));		ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;		ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;		ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;		return ret;	}}

 

声明:算法不是出自本人,以整理验证通过

转载于:https://my.oschina.net/huqiji/blog/804854

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